h^2+1.5h-280=0

Solution for h^2+1.5h-280=0 equation:

h^2+1.5h-280=0

a = 1; b = 1.5; c = -280;
Δ = b2-4ac
Δ = 1.52-4·1·(-280)
Δ = 1122.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{1122.25}}{2*1}=\frac{-1.5-\sqrt{1122.25}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{1122.25}}{2*1}=\frac{-1.5+\sqrt{1122.25}}{2}
$